Me .use each digits 2,3,7,8 to make numbers from 20,21,22 so on all the way to 50 for example 2+3+7+8=20

Sorry for the delayed time, it took me a little to be able to figure out how to use every digit to get every number, but I did it, and that was a lot of thinking (jeez my brain hurts now)...

Hope this helps...

GIVEN: 20 = 2+3+7+8

21 = 7*((8-3)-2)

22 = ((8+7-3)*2)-2

23 = ((8*(7-2))+3)/2

24 = (((8*((7/2)+3))/2)-3

25 = ((8*7)/2)-3

26 = (((8+(2-3))*7)-3)-((7+3)*2)

27 = (((8+(2-3))*7)-2)-((7+3)*2)

28 = (((8+(2-3))*7)+(2-3))-((7+3)*2)

29 = ((8+(2-3))*7)-((7+3)*2)

30 = (8*(7-3))-2

31 = (8*(3+2))-(7+2)

32 = (8*(3+2))-(7-(2-3))

33 = (8*(3+2))-7

34 = (8*(3+2))-(7+(2-3))

35 = (8*(3+2))-(7-2)

36 = (8*(3+2))-(7-3)

37 = (8*(3+2))-(7-(2+2))

38 = (8*(3+2))-(7-(2+3))

39 = (8*(3+2))-(7-(3+3))

40 = (8*7)-((7+3)+(2*3))

41 = (8*7)-((7+3)+(2+3))

42 = (8*7)-((7+3)+(2+2))

43 = (8*7)-((7+3)+(2*3)-3)

44 = (8*7)-((7+3)+2)

45 = (8*7)-((7+3)+(3-2))

46 = (8*7)-((3*2)+(2*2))

47 = (8*7)-((3*2)+3)

48 = (8*7)-((7+(3-2))

49 = (8*7)-((2*2)+3)

50 = 2*3*7+8

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!