Which value is the 14th term of the sequence
1/81, 1/27, 1/9, 1/3, 1
a. 6561
b. 59049
c. 2187
d. 19683

This is a geometric sequence because it has a common ratio, denoted r, meaning that each term is a multiple of the previous term.

, a=initial term, r=common ratio, n=term number

In this case a= and r=3 (because each term is 3 time the previous term) so



So the 14th term is:

a(14)=(1/81)=59049

Where is the problems