Arectangle has a length that is 5 inches greater than its width, and its area is 104 square inches. the equation (x + 5)x = 104 represents the situation, where x represents the width of the rectangle. what are the dimensions of the rectangle?

1. Regroup terms
x(x+5)=104

2. Expand
x^2+5x=104

3. Move all terms to one side
x^2+5x-104=0

4. Factor x^2+5x-104
(x-8)(x+13)=0

5. Solve for x
x=8 or x=-13
Since x<0 is not possible in this case, x=8

6. Finding the dimensions
We know that one side has to be x+5, and now that we know x:
8+5=13
13*8=104

The dimensions are 13 and 8, have a nice day :D

Ithink the answer is a