The area on the wall covered by a rectangle poster is 320 square inches. the length of the poster is 1.25 times longer than the width of the poster. what are the dimensions of the poster?

Length = 20 inches

Width = 16 inches

Step-by-step explanation:

The area on the wall covered by a rectangle poster is 320 square inches.

The length of the poster is 1.25 times longer than the width of the poster.

Let x be the width of the poster.

Length of the poster = 1.25x

Area of a rectangular poster is

Divide both sides by 1.25.

Taking square root on both sides.

The dimensions can not be negative. So, x=16.

Length of the poster = 1.25(16)=20

Therefore, the length of the poster is 20 inches and width of the poster is 16 inches.

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length