Arectangular garden has a length that is six feet more than twice its width. it takes 120 feet of fencing to completely enclose the gardens area

L = 42

W = 18

Step-by-step explanation:

I'm assuming that you want to know the width and the length of the garden. The procedure to do this is the following:

First, we know that the Length is 6 feet more than twice the width, this in other words, means:

L = 6 + 2W

So, let's call W as X

The perimeter of the garden is 120 and the expression to calculate is:

P = 2W + 2L

Replacing all the values in the above expression we have the following:

120 = 2x + 2(6 + 2x)

Solving for x we have:

120 = 2x + 12 + 4x

120 - 12 = 6x

108 = 6x

x = 108/6

x = 18

So the Width is 18, therefore the Length:

L = 6 + 2(18)

L = 6 + 36

L = 42

- (2, -7)

- lines r and s and lines t and u must be parallel