Which equation would best solve the following problem?
the height of a triangle is 6 m more than its base.
the area of the triangle is 56 m2. find the length of the base.
question 1 options:
56=1/2(x)(x+6)
56=12(x^2+6)
56=(x)(x+6)
56=x^2+6

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204