Jim says that a 2 1/2 inche by 3 1/4 inch rectangle has a section that is 2 inches x 3 inches and a section that is 1/2 inch x 1/4 inch. that means that area is just the sum of these two smaller areas, or 6 1/8 inches times 2 powers of ten. why is jim incorrect? use an area model to explain your thinking. then, give the correct area of the rectangle.

Area of the rectangle is 8¹/₈ in²

To solve the above questions, we need to recall some of the formulas as follows:

Area of Square = (Length of Side)²

Perimeter of Square = 4 × (Length of Side)

Area of Rectangle = Length × Width

Perimeter of Rectangle = 2 × ( Length + Width )

Area of Rhombus = ½ × ( Diagonal₁ + Diagonal₂ )

Perimeter of Rhombus = 4 × ( Length of Side )

Area of Kite = ½ × ( Diagonal₁ + Diagonal₂ )

Perimeter of Kite = 2 × ( Length of Side₁ + Length of Side₂ )

Let us now tackle the problem !

Given:

Length of Rectangle = L = 2¹/₂ in

Width of Rectangle = W = 3¹/₄ in

Unknown:

Area of Rectangle = A = ?

Solution:

This problem is about Area of Rectangle.

Jim is incorrect because he only calculated 2 of the 4 available sections of the rectangle ( as shown in the diagram ).

Grade: College

Subject: Mathematics

Chapter: Two Dimensional Figures

Keywords: Perimeter, Area , Square , Rectangle , Side , Length , Width

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.

i think it might be a but you might want a second opinion