What is the probability that a point chosen at random in the given figure will be inside the smaller square?

enter your answer, as a fraction in simplest form, in the box.
p(inside smaller square) =

smaller square = 3cm
bigger square= 5cm

I have to interpret that:

1) the smaller square has side length = 3 cm

2) the bigger square has side length = 5 cm

3) the smaller square is completely inside the bigger square.

4) the points cannot be outside the bigger square

Under those assumptions the probability that a point is inside the smaller square  is

P (inside the smaller square) = area of the smaller square / area of the bigger square

P (inside the smaller squere) = (3cm)^2 / (5cm)^2 =  9 / 25

9 / 25

21

step-by-step explanation:

21-4