Point p is the center of two concentric circles. pq = 4.2 and ps = 8.2. mc027-2.jpg is tangent to the smaller circle and a chord of the larger circle. what is length to the nearest tenth?

The length of the chord is 14.1 units.

Step-by-step explanation:

Given : Two concentric circles with common center Point P.

Smaller circle with radius, PQ = 4.2 unit

Bigger circle with radius, PS = 8.2 unit

Tangent to the smaller circle is a chord of the larger circle.

To find: Length of the chord , RS

Solution:

Perpendicular drawn from the center of the circle to the chord bisect the chord. So,

SQ = QR

In given figure, ΔPSQ

(Pythagoras theorem)

RS = SQ + QR = 7.042 units+7.042 units = 14.084 units ≈ 14.1 units.

The length of the chord is 14.1 units.

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17