Achicken farm orders bags of feed from two farmers. store x charges $20 per bag, and store y charges $15 per bag. the farm must obtain at least 60 bags per week to care for the chickens properly. store y can provide a maximum of 40 bags per week, and the farm has committed to buy at least as many bags from store x as from store y. the chicken farm wants to minimize the cost of ordering feed. let x represent the number of bags of feed from store x and y represent the number of bags of feed from store y. what are the constraints for the problem?

x + y ≥ 60;

y ≤ 40;

x ≥ y;

x ≥ 0, y ≥ 0

Step-by-step explanation:

Here x represents the number of bags of feed from store X and y represents the number of bags of feed from store Y.

Given,

The farm must obtain at least 60 bags per week to care for the chickens properly,

⇒ x + y ≥ 60,

Also, Store Y can provide a maximum of 40 bags per week, and the farm has committed to buy at least as many bags from store X as from store Y.

⇒ y ≤ 40 and x ≥ y,

Now, the number of bags can not be negative,

⇒ x ≥ 0 and y ≥ 0,

Hence, the constraints for the given problem are,

x + y ≥ 60;

y ≤ 40;

x ≥ y;

x ≥ 0, y ≥ 0

6.9

step-by-step explanation:

simple math really

6 1/2 times 0.6 = 3.9

but if you are just doing 6 and not 6 1/2 then the answer is 3.6

answer: approximately 206 bones

i hope this u out a branlist and a would be greatly appreciated :