Solve algebraically: the soccer field has an area of 6000 square yards. the field is 40 yards longer than its width. what are the dimensions of the field in years

Lets width od field is x , x>0 (if x<0 it is no sense) yards and length is (x+40)yards
So square of field is x(x+40)=6000
x²+40x=6000
x²+40x-6000=0
(x+100)(x-60)=0
x₁=-100 no sense
x₂=60 yards - width of field
x+40=x+60=100 yards - length of field
60 yards - width of field, 100 yards - length of field
 

A= r2 × 3.14 7x7 ↓ ↓ 49 × 3.14 = 153.86 → 153.9

32.68 the is the !