Use the remainder theorem to explain whether or not (x-2) is a factor of f(x)=x^4-2x^3+3x^2-10x+3

ok

Step-by-step explanation:

\frac{P(x)}{R(x)}|\frac{D(x)}{Q(x)}

\frac{x^4-2x^3+3x^2-10x+3}{}|\frac{x-2}{}

\frac{x^4-2x^3+3x^2-10x+3}{-x^4+2x^3}|\frac{x-2}{x^3}

\frac{3x^2-10x+3}{-3x^2+6x}|\frac{x-2}{x^3+3x}

\frac{-4x+3}{4x-8}|\frac{x-2}{x^3+3x-4}

\frac{-5}{}|\frac{x-2}{x^3+3x-4}

\boxed{\boxed{\frac{x^4-2x^3+3x^2-10x+3}{-5}|\frac{x-2}{x^3+3x-4}}}

R(x)=-5

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13