Aball is thrown in the air from a ledge. its height in feet is represented by
f(x) = –16(x2 – 6x – 7), where x is the number of seconds since the ball has been thrown. the height of the ball is 0 feet when it hits the ground.
how many seconds does it take the ball to reach the ground?

The time taken by the ball to reach the ground is 7 seconds.

Step-by-step explanation:

Given : A ball is thrown in the air from a ledge. Its height in feet is represented by  , where x is the number of seconds since the ball has been thrown. The height of the ball is 0 feet when it hits the ground.

To find : How many seconds does it take the ball to reach the ground?

Solution :

The function  

represent the height of the ball.

Where, x is the number of seconds.

We have given that the height of the ball is 0 feet when it hits the ground

and we to find the seconds does it take the ball to reach the ground.

i.e., we have to take f(x)=0 and find x.

Applying middle term split,

x=-1 is rejected as time is not negative.

x=7 is accepted.

Therefore, The time taken by the ball to reach the ground is 7 seconds.

step-by-step explanation:

$25

step-by-step explanation:

25 - 4.50 = 20.5

20.5 / 2 = 10.25

10.25 + 10 = 20.25

20.25 - 12.50 = 7.75

therefore the answer is $25 as shown as the first number.