If the outliers are not included, what is the mean of the data set?

72, 82, 3, 55, 62, 73, 90, 80, 151, 59, 46, 31

a.59
b. 65
c. 67
d. 73

3,31,46,55,59,62,72,73,80,82,90,151

Q1 = (46 + 55) / 2 = 101/2 = 50.5
Q2 (median) = (62 + 72) / 2 = 134/2 = 67
Q3 = (80 + 82) / 2 = 162/2 = 81

IQR = Q3 - Q1 = 81 - 50.5 = 30.5
30.5 * 1.5 = 45.75

Q1 - 30.5 = 50.5 - 30.5 = 20.5...so anything less then 20.5 is an outlier
Q3 + 30.5 = 81 + 30.5 = 111.5...anything more then 111.5 is an outlier

so ur outliers are : 3 and 151

now we find the (mean)average...
(72+82+55+62+73+90+80+59+46+31) / 10 = 650/10 = 65 <==

Answer is either b or c

Heptagon is the correct ans