The length of the rectangle is 4 times the height. the area of the triangle is 63 cm2. find the width. round to the nearest tenth of an inch

area = l x h

l=4h

area = 4h x h = 4h^2

4h^2 =63

63/4 = 15.75

h^2 = 15.75

sqrt(15.75)=h

h = 3.968cm

rounded to nearest tenth would be 4.0cm

check L=4(4) = 16 x 4 = 64 ( since it was round 64 is pretty close to 63)

so the possibilities of the measurement of the side of the triangle are either it is longest side or not the longest side

when it is the longest side

s < 25 + 35s < 60

if it is not the longest side

35 < 25 + s10 < sso 10 < s < 60so the perimeter70 < p < 130