Identify the graph of the equation. what is the angle of rotation for the equation? 13x^2+6sprt3xy+7y^2-16=0

We are given the equation:

13x^2 + 6√3 xy + 7y^2 - 16 = 0

Based on the general equation of conic sections:

Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0,

A = 13
B = 6√3
C = 7
D = 0
E = 0
F = -16

So we can find the graph of the equation by solving for the discriminate B^2 - 4AC 

B^2 - 4AC, substitute given:

(6^2 * 3) - 4 (13 * 7) = -256

since the discriminate is less than zero, the graph could be a circle or a parabola. In this case, the values of A and C are not equal, then our graph is a parabola. 

Iwould say they are complementary because that’s the division of a 90 degree angle and it’s split between the middle of them