There are 52 white keys and 36 black keys on a standard piano. what is the probability that if a person did not look and hit the keyboard twice that he or she would first hit a white key and then hit a black key?

 The required probability is

Step-by-step explanation:  Given that there  are 52 white keys and 36 black keys on a standard piano. A person did not look and hit the keyboard twice.

We are find the probability that the person first hit a white key and hit a black key.

Let A and B represents the events that the person hit a white key and a black key respectively.

Then, the probabilities of events A and B are given by

Since the events A and B are independent of each other, so the probability that the person first hit a white key and hit a black key is given by

Thus, the required probability is

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1