If ef bisects cd, cg=5x-1, gd=7x-13, ef=6x-4, and gf=13, find e. g.
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Hello there,

The first thing to take into account is:

“EF bisects CD”.

In geometry, “bisects” means to dive into two exactly equal parts.

If EF bisects CD on G, CG measures the same as GD

CG = GD

5x - 1 = 7x - 13

12 = 2x

6 = x

Now you know the value of “x”.

If EF = 6x - 4 and x = 6, EF = 6*6-4 =32

EF = EG + GF

32 = EG + 13

So, EG = 19

Kind regards,

Daniela

the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

the root or roots of a polynomial are the values of the variable that makes the polynomial equal to 0. we can find the roots of a polynomial making the expression equal to 0 and then, isolating the variable (it it has just one variable).

for example, given the following polynomial:

the root or zero of the polynomial, can be found by making the expression equal to 0, and then, isolating the variable, so, finding the root we have:

therefore, we have that the root of the polynomial is equal to 2.

we must remember that the number of roots that a polynomial can have, will depend on the degree of the polynomial, a first degree polynomial have will have one single root, a second degree polynomial (quadratic expression) may have two roots and so.

hence the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

have a nice day!