Consider the algebraic expressions 3x, 9x, 4x, 23x, 6x and 3x. assume x> 0.
part a) find the mean, median, and mode.
part b) is there an outlier? if so, what is it?

Mean: This is an average of all the numbers. Add up the numbers and then divide by how many numbers there are.

(3+9+4+23+6+3)/6 = 48/6 = 8

Median: The number in the middle, when the numbers are in order. If there are 2 middle numbers, average them together.

3, 3, 4, 6, 9, 23 : 4 and 6 are the middle numbers. 4+6/2 = 10/2 = 5

Mode: What value occurs most frequently? 3 is the only duplicate

Outlier: What value is abnormal to our set of data? All of our numbers are small (single digits), except for 23. That makes it an outlier.

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm

Bi’m pretty sure hope it works