Let f(x) = x2 – 16 and g(x) = x + 4. find f/g and its domain.

a. x + 4; all real numbers except x ≠ –4
b. x – 4; all real numbers except x ≠ –4
c. x - 4; all real numbers except x ≠ 4
d. x + 4; all real numbers except x ≠ 4

The correct option is B, i.e., x – 4; all real numbers except x ≠ –4.

Explanation:

It is given that,

We have to find the function .

Using

Hence the fountain is (x-4).

The domain of is the intersection of domain of both function except the the values for which the value of denominator function 0.

Since the domain of f(x) and g(x) is all real numbers but the g(x) is 0 at x=-4, therefore the domain of is all real numbers except x ≠ –4.

Therefore, the correct option is B.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

it's both, now can you answer my most recent question?