Point P is plotted on the coordinate grid. If point S is 10 units above point P, what are the coordinates of point S? On a coordinate grid from negative 12 to positive 12 in increments of 2, a line PQ is drawn with P plotted at the ordered pair 6, negative 4.
(1 point)

1. (−4, −4)
2. (−4, 6)
3. (6, 6)
4. (6, −4)

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Step-by-step explanation:

(−4, −4)

2. (−4, 6)

3. (6, 6)

4. (6, −4)

45 minutes

step-by-step explanation:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

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