a skydiver jumps out from the plane at 10,000 feet above the ground. the skydiver decends at a rate of 175 feet per seconds. how high in the air is the skydiver when he opens his parachute after 25 seconds?

5625 feet

I hope it's helps you

5625 feets

Step-by-step explanation:

Rate(feet/seconds) = height(feets)/time(seconds)

175 = x/25

x = 4375

After the skydiver opens his parachute the height reduces

Initial height – reduced height

10000 – 4375

= 5625 feets

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.

it should be a and d. lmk if i'm wrong xd