Suppose that Clayton Kershaw of the Los Angeles Dodgers throws his fastball with a mean velocity of 94 miles per hour (mph) and a standard deviation of 2 mph and that the distribution of his fastball speeds can be modeled by a Normal distribution What percent of Kershaw’s fastballs will travel at least 100 mph?

Step-by-step explanation:

ah,  probability,  so the std. deviation is 2 MPH,  so that means to get from the mean.. or average speed of 94, he'll have to vary by 3 std. deviations  or  6 MPH to hit 100

99.7%  of throws fall into that area of with in 3 std. deviations so that means

0.3% fall outside also , 1/2 of those will 3 std. deviations slow while the other half is fast

so

0.15%  will be 100 or faster not many

answer: i believe the answer is e

step-by-step explanation: