Mathematics, 04.05.2021 01:00 ryanmorse01
Solve for yyy.
Assume the equation has a solution for yyy.
a\cdot(n+y) = 10y+32a⋅(n+y)=10y+32a, dot, left parenthesis, n, plus, y, right parenthesis, equals, 10, y, plus, 32
y=y=y, equals
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Solve for yyy.
Assume the equation has a solution for yyy.
a\cdot(n+y) = 10y+32a⋅(n+y)=10y+3...
a\cdot(n+y) = 10y+32a⋅(n+y)=10y+3...
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