A space probe communicates with NASA using bit strings. Suppose that for each bit it sends, the probability that it is a 1 is 0.3, so the probability that it is a 0 is 0.7. Now an issue with these kinds of communication is that occasionally the bits flip. Suppose NASA has observed that the probability a bit flips is 0.1. This means that the probability that NASA receives a 1 given that the space probe sent a 0 is 0.1; similarly, the probability that NASA receives a 0 given that the space probe sent a 1 is 0.1. Let SO and S1 denote the events that the space probe sent a 0 and a 1 respectively. On the other hand, let RO and R1 be the events that NASA received a 0 and a 1 respectively.

a. Write the values of Prob(S1), Prob(SO), Prob(R1/SO), Prob(RO/S1) from the problem statement.
b. What is Prob(S1n RO)? (i. e., the probability the space probe sent a 1 and NASA received a 0)
c. What is Prob(SO n RO)?
d. What is Prob(RO)?
e. Finally, what is Prob(SORO)?

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step-by-step explanation:

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answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

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step-by-step explanation:

when the line is solid:

when the line is dashed:

this > inequality sign means:

this < inequality sign means:

this > inequality sign means:

this < inequality sign means:

about the problem:

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