You pick a card at random. Without putting the first card back, you pick a second card at random.
123
What is the probability of picking a 2 and then picking a 1?
Write your answer as a fraction or whole number.

1/6

Step-by-step explanation:

Firstly, Pr(e) = n(e)/Total outcome

Pr(2) = 1/3

Pr(1) = 1/2

Pr(1 and 2) = 1/3 * 1/2 = 1/6

the answer is 5/3x+7/5y+7

i think it's either c or d

step-by-step explanation: the entire question is extremely odd. 04 obviously refers to the interest rate. honestly i will say the answer is c. because the (2 x 12) part would mean it's compounded semiannually. i'll say choose c.