Air pressure decreases exponentially with increases in elevation. The air pressure, y, (in atm units) at a given elevation, I, (in meters) can be modeled using equation y = e-los, where k is the decay constant.
At an elevation of 5486 m where the air pressure is 0.5 atm, what is the value of k?
A k=
In( 5486)
0.5
O B. k=
In(0.5)
5486
Ock=-In ( 545
D. k=-In ( 59.56

54 km / hours

step-by-step explanation:

we need to convert seconds to hours

60 seconds = 1 minutes

60 minutes = 1hour

15 m         60 second   60 minutes

  * *         = 54000 meters/ hour

second     1 minute             1 hour

now we need to convert meters to km

1000 m = 1 km

54000 m       1 km

*   = 54 km / hours

hour               1000m

i think the amount would be $140.62

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.