X = [-b ± √(b2 – 4ac)] /2a · am x b m = (a x b)m; am x a n = (a)
what is this?...
Mathematics, 26.05.2021 20:00 kimly47
X = [-b ± √(b2 – 4ac)] /2a · am x b m = (a x b)m; am x a n = (a)
what is this?
Answers: 2
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