The current altitude of the plane is 15400 feet above the ground and the plane's horizontal distance to the airport is 200000 miles away. What angle of depression must the pilot make on his descent in order to safely land on the runway>

0.441°

Step-by-step explanation:

tan = 1540/200000

tan = 0.0077

tan-1(0.0077) = 0.441

angle of depression is 0.0441°

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.