Which of the following functions is graphed below? y= {x^2 + 3, x _> 4
x + 4, x < 4}

y= {x^2 + 3, x > 4
x + 4, x _< 4}

y= {x^2 + 3, x < 4
x + 4, x _> 4}

y= {x^4 + 3, x _< 4
x + 4, x > 4}

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0

b

step-by-step explanation:

question: match the eqaution with its graph -8x - 5y = 40

answer: 8 x 5 = 40

x= absiss

y= orderly

so you have a proportional graph

question answered by

(jacemorris04)

good luck on ur quiz test or homework. have a good day : )