if the wheel of a bullock cart has a diameter of 12cm with angle 60°. if the width rotate once how much distance does the cart move?. what is the area of the sector.​

im not too good with this but can factorise the wheels meteres, hope it answers ur question? lmk

Step-by-step explanation:

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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