Find the consecutive odd numbers such that 6 times the smaller plus 3 times the larger comes to 105​

11 and 13

Step-by-step explanation:

let smaller odd number be x

larger odd nuber be x+2

according to the question algebraic expression can be written as

6x+3(x+2)=105

6x+3x+6=105

9x=105-6

9x=99

x=99/9

x=11

larger number=x+2

11+2

13

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -