The question relates to the sum of an arithmetic progression, A. P.
The count of numbers added, n = 50
The sum of the numbers, Sₙ = 3,250
The formula for the sum of an A. P. is given as follows;
a = The first term of set of numbers
d = The common difference between consecutive numbers
n = The number of terms = 50
aₙ = The last term, the largest of the integers
Therefore, we get;
The common difference of consecutive even integers numbers, d = 2
Plugging in the values gives;
3,250 = (50/2) × (2·a + (50 - 1) × 2) = 25 × (2·a + 49 × 2)
2·a = (3,250/25) - 49 × 2 = 32
a = 32/2 = 16
From , we have;
3,250/25 = 16 + aₙ
aₙ = 3,250/25 - 16 = 114
The largest of the integers, aₙ = 114.
i think thats the answer i checked it on google
we are given the following expression and we are to solve it and find the product:
-13 × (-5)
solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.
-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)