The accompanying observations are numbers of defects in 25 1-square-yard specimens of woven fabric of a certain type: 4, 7, 5, 2, 3, 1, 9, 3, 4, 3, 5, 7, 3, 2, 2, 4, 7, 3, 2, 5, 5, 1, 4, 4, 5. Construct a c chart for the number of defects. (Round your answers to two decimal places.) x double bar =
LCL =
UCL =

x double bar = 4

LCL = - 2

UCL = 10

Step-by-step explanation:

The C - chart :

The control limit = xbar

xbar = mean = ΣX / n

The upper and lower control limit :

Xbar ± 3√xbar

Xbar = Σx / n = 100 / 25 = 4

Hence,

x double bar = 4

LCL = Xbar - 3√xbar = 4 - 3√4 = 4 - (3*2)

LCL = 4 - 6 = -2

UCL = Xbar + 3√xbar = 4 + 3√4 = 4 + (3*2)

LCL = 4 + 6 = 10

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.