Rotate triangle P 90° clockwise about the point (2, -1). y 51 4 3 2 1 Х -5 -4 -3 -2 -1 0 - 1 1 1 2 3 4 5 P -2 -3 -4 -5​

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

Given: m∠ adb = m∠cdb ad ≅ dc prove: m∠ bac = m∠bca lol

Find the values of the variables in the kite