Find f(x+2) of the function f(x)= 4x^2+2x-4 HELP ASAP PLEASE WORTH 40 POINTS

The functional expression can be simplified by substituting the given value in the function in place of the variable.

For example, if {eq}f(x)=x^{2} {/eq} be a function then {eq}f(2) {/eq} is determined by plugging {eq}x=2 {/eq} in the function.

Step-by-step explanation:

The given function is:

{eq}f(x) = 4x^{2} + 2x {/eq}

Let {eq}y=\frac{f(x + h) - f(x)}{h} {/eq} then we have:

{eq}begin{align*} y & = \frac{4(x+h)^{2} + 2(x+h)-(4x^{2}+2x)}{h} & = \frac{4(x+h)^{2} + 2(x+h)-(4x^{2}+2x)}{h} & = \frac{4(x^{2}+2xh+h^{2}) + 2x+2h-4x^{2}-2x}{h} & = \frac{4x^{2}+8xh+4h^{2}+ 2h-4x^{2}}{h} & = \frac{8xh+4h^{2}+ 2h}{h} & = \frac{h(8x+4h+2)}{h} & = 8x+4h+2 end{align*} {/eq}

Given

To find f(x + 2) substitute x with x + 2 in the given function:

f(x+2)= 4(x + 2)² + 2(x + 2) - 4

         = 4(x² + 4x + 4) + 2x + 4 - 4

         = 4x² + 16x + 16 + 2x

         = 4x² + 18x + 16

answer: x

step-by-step explanation:

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step-by-step explanation: