Suppose f(x) = x^2. what is the graph of g(x)

 g(x) = (1/16)*x^2

Explanation:

Plug x = 4 into f(x) to find that f(4) = 16.

The output y = 16 drops to y = 1. We've multiplied by 1/16 to get this to happen.

In other words,

g(x) = (1/16)*f(x)

g(4) = (1/16)*f(4)

g(4) = (1/16)*16

g(4) = 1

So we can say that,

g(x) = (1/16)*f(x)

g(x) = (1/16)*x^2

and furthermore, we can say f(x) has been vertically compressed by a factor of 16.

include a picture of the drawing in order for me to

step-by-step explanation: