What is the value of x in the equation 1/5x - 2/3y
=
30, when y = 15?

x = 200

Step-by-step explanation:

Plug in 15 as y into the equation and solve for x:

1/5x - 2/3y = 30

1/5x - 2/3(15) = 30

1/5x - 10 = 30

1/5x = 40

x = 200

So, when y = 15, x = 200

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

two data sets with the same median will not have the same varaibility

step-by-step explanation: