For 0 degrees ≤ x < 360 degrees , what are the solutions to sin (x/2) + cos(x) - 1 =0

Recall the double angle identity for cosine:

cos(x) = cos(2×x/2) = 1 - 2 sin²(x/2)

Then the equation can be rewritten as

sin(x/2) + (1 - 2 sin²(x/2)) - 1 = 0

sin(x/2) - 2 sin²(x/2) = 0

sin(x/2) (1 - 2 sin(x/2)) = 0

sin(x/2) = 0   or   1 - 2 sin(x/2) = 0

sin(x/2) = 0   or   sin(x/2) = 1/2

[x/2 = arcsin(0) + 360n °   or   x/2 = 180° - arcsin(0) + 360n °]

… …   or   [x/2 = arcsin(1/2) + 360n °   or   x/2 = 180° - arcsin(1/2) + 360n °]

x/2 = 360n °   or   x/2 = 180° + 360n °

… …   or   x/2 = 30° + 360n °   or   x/2 = 150° + 360n °

x = 720n °   or   x = 360° + 720n °

… …   or   x = 60° + 720n °   or   x = 300° + 720n °

(where n is any integer)

We get only three solutions in 0° ≤ x < 360° :

720×0° = 0°

60° + 720×0° = 60°

300° + 720×0° = 300°

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00