Determine X and Y
(2+i) (x+yi) = -7+3i​

x=-11\5+13\5i-iy

y=ix+(13\5+11\5i)

Step-by-step explanation:

x+yi=-7+3i\2+i

x+yi=\frac{\left(-7+3i\right)\left(2-i\right)}{\left(2+i\right)\left(2-i\right)}

x+yi=-11\5+13\5i

x=-11\5+13\5i-yi

x=-11\5+13\5i-iy

x+yi=\frac{-7+3i}{2+i}

x+yi=\frac{\left(-7+3i\right)\left(2-i\right)}{\left(2+i\right)\left(2-i\right)}

x+yi=\frac{-11+13i}{5}

x+yi=-\frac{11}{5}+\frac{13}{5}i

yi=-\frac{11}{5}+\frac{13}{5}i-x

\frac{iy}{i}=\frac{-\frac{11}{5}+\frac{13}{5}i-x}{i}

y=\frac{-\frac{11}{5}+\frac{13}{5}i-x}{i}

muyb ajo

step-by-step explanation:

jegosu

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation: