1+-2/3--m where m=9/2

-25/9

Step-by-step explanation:

1 + (-2/3) - m

Plug in:

1 + (-2/3) - 9/2

1 + 2/3 - 9/2

1/3 - 9/2

-25/9

Hope this helped.

4 5/6

Step-by-step explanation:

1+-2/3--m

Subtracting a negative is like adding

1-2/3 +m

1/3+m

m = 9/2

1/3 +9/2

Get a common denominator of 6

1/3 *2/2 +9/2*3/3

2/6 + 27/6

29/6

Changing to a mixed number

4 5/6

answer: the answer to your question is parallel

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)