The length of a rectangle is 2 inches more than its width. The area of the rectangle is equal to 1 inches less than 3 times the perimeter. Find the length and width of the rectangle.

The length is 13, when the width is 11

Step-by-step explanation:

The width is x, when the length is x+2. The area is x(x+2)= x^2+2x.

The perimeter is (x+x+2)*2= (2x+2)*2=4x+4

THe thrre times perimeter is 3(4x+4)= 12x+12

x^2+2x= 12x+12-1

x^2+2x-12x-11=0

x^2-10x-11=0

x=-1 (not suitable); x=11 - the width

The length is 11+2=13

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2