For each pair of equations, write the letter of the equation that expresses an equal value. 1. a. L = 1 dm3 b. 1 L = 1 cm3
2. a. 1 mL = 1 cm3 b. 1 cm3 = 1 L
3. a. 0°C = –273 K b. 0 K = −273°C
4. a. 1 kg = 100 g b. 1,000 g = 1 kg
5. a. 400 cm = 4.0 m b. 400 cm = 0.40 m
6. a. 1 dm = 10 m b. 1 dm = 0.10 m
7. a. 100°C = 373 K b. 373 K = 10°C

We must understand that certain standards has been layed down for the conversions of measuring units. A summary of such standards are discussed below:

1. Option A. 1 L = 1 dm³

2. Option A. 1 mL = 1 cm³

3. Option B. 0 K = −273 °C

4. Option B. 1000 g = 1 kg

5. Option A. 400 cm = 4.0 m

6. Option B. 1 dm = 0.10 m

7. Option A. 100°C = 373 K

1. Option A. 1 L = 1 dm³

Option B. 1 L = 1 cm³

From standard measurement,

1 L = 1 dm³

1 L = 1000 cm³

From the measuring standard, we can see that 1 L  ≠ 1 cm³.

Hence, option A gives the correct answer.

2. Option A. 1 mL = 1 cm³

Option B. 1 cm³ = 1 L

Hence, option A gives the correct answer.

From standard measurement,

1 mL = 1 cm³

1000 cm³ = 1 L

Thus, option A gives the correct answer.

3. Option A. 0°C = –273 K

Option B. 0 K = −273 °C

Recall:

T (K) = T(°C) + 273

T (K) = Temperature in Kelvin

T(°C) = Temperature in decree celcius

Next, we shall convert 0°C to K

T(°C) = 0°C

T (K) = T(°C) + 273

T (K) = 0 + 273

T (K) = 273 K

Thus, 0°C is equivalent to 273 K

Next, we shall convert 0 K to °C

T(K) = 0

T (K) = T(°C) + 273

0 = T(°C) + 273

Collect like terms

0 – 273 = T(°C)

T(°C) = –273°C

Thus, 0 K is equivalent to –273°C

Therefore, option B gives the correct answer.

4. Option A. 1 kg = 100 g

Option B. 1000 g = 1 kg

From standard measurement,

1 Kg = 1000 g

1000 g = 1 Kg

Hence, Option B gives the right answer

5. Option A. 400 cm = 4.0 m

Option B. 400 cm = 0.40 m

From standard measurement,

100 cm = 1 m

Converting 400 cm to m, we have:

Thus, option A gives the correct answer.

6. Option A. 1 dm = 10 m

Option B. 1 dm = 0.10 m

From standard measurement,

10 dm = 1 m

Thus,

Therefore, option B gives the correct answer.

7. Option A. 100°C = 373 K

Option B. 373 K = 10°C

Recall:

T (K) = T(°C) + 273

T (K) = Temperature in Kelvin

T(°C) = Temperature in decree celcius

Next, we shall convert 100°C to K

T(°C) = 100°C

T (K) = T(°C) + 273

T (K) = 100 + 273

T (K) = 373 K

Thus, 100°C is equivalent to 373 K

Next, we shall convert 373 K to °C

T(K) = 373

T (K) = T(°C) + 273

373 = T(°C) + 273

Collect like terms

373 – 273 = T(°C)

T(°C) = 100°C

Thus, 373 K is equivalent to 100°C

Therefore, option A gives the correct answer.

SUMMARY:

1. Option A. 1 L = 1 dm³

2. Option A. 1 mL = 1 cm³

3. Option B. 0 K = −273 °C

4. Option B. 1000 g = 1 kg

5. Option A. 400 cm = 4.0 m

6. Option B. 1 dm = 0.10 m

7. Option A. 100°C = 373 K

Learn more:

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above