4x+11=x²-10
PLS HELP.

10+4x+11=x²-10+10 (add 10 both side)

21+4x-4x=x^2-4x  (substract 4x in both side)

21-21=x^2-4x-21 (substract 21 in both side)

x^2-4x-21=0

x^2+3x-7x-21=0(we can write -4x as (3x)+(-7x)=(-4x)

x(x+3)-7(x+3)=0 (get common factor)

(x+3)(x-7)=0 (get common factor which is (x+3) by both)

x=-3 or x=7

Step-by-step explanation:

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions