30 points no fake answers! Plzzz help! A truck driver is driving from Nome, Alaska to Death Valley, California. Because he is traveling between locations with extreme temperatures, he needs to check the weather continuously to make sure the gas in his truck remains in liquid form. The gas he uses freezes at −40° F and evaporates at 140° F.

Part A: Write an inequality to represent the temperatures at which the gas in the truck will remain in liquid form. (2 points)

Part B: Describe the graph of the inequality completely from Part A. Use terms such as open/closed circles and shading directions. Explain what the solutions to the inequality represent. (4 points)

Part C: In January 1989, the temperature in Nome, Alaska dropped to −49° F. Would the gas in the driver's truck have remained in liquid form so he could have driven on this day? Why or why not? (4 points)

Part A : -40F < x < 140F

Part B: the graph would have two open circles at x = -40 and x = 140, and would be shaded in between -40 and 140.

Part C: Simple No it wouldn't

Step-by-step explanation:

Complex answer to part c:

The gas would remain a liquid, because a gas engine creates a lot of heat, meaning that if you put the gas outside, it will freeze, but inside the truck, it won't freeze.

**BUT THE ANSWER IS PROBABLY JUST THE SIMPLE ONE**

Hello!

A. -40 < T < 140

From the question, we are informed that the gas that the driver uses freezes at −40° F and evaporates at 140° F.

To get the inequality to represent the temperatures at which the gas in the truck will remain in liquid form, we should note that the temperature will be lower than 140°F but more than -40°F. This can be expressed as:

= -40 < T < 140

B. The line segment would be from point -40 to 140 on the number line. Both points' circles would be open and shaded between them.

C. The gas would freeze because -49° F is smaller than -40° F.

Step-by-step explanation:

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d.192

step-by-step explanation:

12*16=192