The two sides of a right triangle differ by one. If the hypotenuse is 29 cm, then determine the lengths of the two sides.

Let the sides be a and b

a^2 + b^2 = c^2 = 29^2 = 841

a^2 + (a + 1)^2 = 841

a^2 + a^2 + 2 a + 1 = 841

2 a^2 + 2 a = 840

a (a + 1) = 420

21 * 20 = 420     trial and error

So the sides are 20 and 21

20^2 + 21^2 = 29^2

hi,

6x times 4 is 24x and 5 times 4 is 20, so the answer is 24x+20.

hope this and for a little humor i am groot.

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0