What is the next step to inscribe a regular hexagon in Circle 0 below? Draw the diameter AB
Through the center 0, draw five more radii.
А
At point A, draw an obtuse angle.
With compass point at A, construct an arc of length
O A intersecting the circle.
Done

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation: