Determine which relation is a function. 0 {(-5, 1), (-5,0), (-2, 1), (-1, 4), (6, 2)}
0 {(-5, 1).(-2, 0), (-1, 1), (2, 4), (6,3)}
O {(-5, 1), (-2, 0), (-2, 2), (3, 4), (6, 2)}
O {(-5, 3), (-2, 0), (-1, 2), (6, 4), (6,3)}

grab rope, tie a loop-de-loop, put it around ur neck, now jump while its tied to a high place. now your shoes are cool.

step-by-step explanation:

what i would say the best answer is a. 40.5

answer: c. is your answer

step-by-step explanation: get me a black leather coat

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)