In an arithmetic sequence, if a2=5 and a10=19 find a6

93

Step-by-step explanation: The first term of AP is -5 and second term means -3.  

Common difference(d) = second term - first term

d = (-3)-(-5)

d= 2

Now using the formula of nth T  

n

=a  

1

+(n−1)d

Here a  

1

=−5,n=50,d=2

Puting these values in the formula of of nth term we get  

a  

n

=−5+(50−1)2

a  

n

=−5+98

a  

n

=93

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.