Graph 24x+25=−6y+7 . please help :)

Given the equation,  −6y + 7= 24x + 25, you'll have to transform this equation into its slope-intercept form, y = mx + b:

−6y + 7 = 24x + 25

Subtract 7 from both sides:

−6y + 7 − 7 = 24x + 25 − 7

−6y = 24x + 18

Divide both sides by −6:

y = -4x - 3 ← This is the slope-intercept form, where m = slope and b = y-intercept.

Next, you need to find at least two points to plot on your graph. We can do this by using the y-intercept, (0, -3). Using the slope, -4 and the y-intercept (0, -3):

Start at (0, -3) then go 4 units down (because it is a negative slope) and 1 unit to the right. Your next point should be (1, -7). You can connect those two points and create a line.    

The attached screenshot shows the graph of the linear equation, y = -4x - 3.

Please mark my answers as the Brainliest if you find my explanations helpful :)

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this